Solve 10x + 10 = ā80
The solution of 10x + 10 = ā80 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 10 = -80\ \Rightarrow\ x = -9 \]
\[ 10x + 10 = -80 \]
\[ 10x + 10 - 10 = -80 - 10 \ \Rightarrow\ 10x = -90 \]
\[ \frac{10x}{10} = \frac{-90}{10} \ \Rightarrow\ x = -9 \]
\[ 10\cdot(-9) + 10 = -90 + 10 = -80 \checkmark \]Trying values of x in 10x + 10 = ā80
| x | 10x + 10 | Equals -80? |
|---|---|---|
| -11 | -100 | no |
| -10 | -90 | no |
| -9 | -80 | yes |
| -8 | -70 | no |
| -7 | -60 | no |
Questions
What is x in 10x + 10 = ā80?
The solution of 10x + 10 = ā80 is x = -9.
How do you solve 10x + 10 = ā80?
Subtract 10 from both sides to get 10x = -90, then divide both sides by 10 to get x = -9.
How do I check the answer?
Replace x by -9: 10(-9) + 10 = -80, which is -80.