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Solve 10x + 10 = āˆ’40

The solution of 10x + 10 = āˆ’40 is x = -5.

The lines y = 10x + 10 and y = -40 meet at x = -5-10-8-6-4-2-100-80-60-40-2020x = -5y = 10x + 10y = -40
The lines y = 10x + 10 and y = -40 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+10=āˆ’4010x + 10 = -40
  2. 2

    Subtract 10 from both sides:

    10x+10āˆ’10=āˆ’40āˆ’10 ⇒ 10x=āˆ’5010x + 10 - 10 = -40 - 10 \ \Rightarrow\ 10x = -50
  3. 3

    Divide both sides by 10:

    10x10=āˆ’5010 ⇒ x=āˆ’5\frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    10ā‹…(āˆ’5)+10=āˆ’50+10=āˆ’40āœ“10\cdot(-5) + 10 = -50 + 10 = -40 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 10 = -40\ \Rightarrow\ x = -5 \]
\[ 10x + 10 = -40 \]
\[ 10x + 10 - 10 = -40 - 10 \ \Rightarrow\ 10x = -50 \]
\[ \frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5 \]
\[ 10\cdot(-5) + 10 = -50 + 10 = -40 \checkmark \]

Trying values of x in 10x + 10 = āˆ’40

x10x + 10Equals -40?
-7-60no
-6-50no
-5-40yes
-4-30no
-3-20no

Questions

What is x in 10x + 10 = āˆ’40?

The solution of 10x + 10 = āˆ’40 is x = -5.

How do you solve 10x + 10 = āˆ’40?

Subtract 10 from both sides to get 10x = -50, then divide both sides by 10 to get x = -5.

How do I check the answer?

Replace x by -5: 10(-5) + 10 = -40, which is -40.

Similar equations

    Solve 10x + 10 = āˆ’40: x = -5 (steps and check) | WordGPT