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Solve 10x + 10 = 20

The solution of 10x + 10 = 20 is x = 1.

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The lines y = 10x + 10 and y = 20 meet at x = 1-4-2246-40-2020406080x = 1y = 10x + 10y = 20
The lines y = 10x + 10 and y = 20 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+10=2010x + 10 = 20
  2. 2

    Subtract 10 from both sides:

    10x+10−10=20−10 ⇒ 10x=1010x + 10 - 10 = 20 - 10 \ \Rightarrow\ 10x = 10
  3. 3

    Divide both sides by 10:

    10x10=1010 ⇒ x=1\frac{10x}{10} = \frac{10}{10} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    10⋅1+10=10+10=20✓10\cdot1 + 10 = 10 + 10 = 20 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 10 = 20\ \Rightarrow\ x = 1 \]
\[ 10x + 10 = 20 \]
\[ 10x + 10 - 10 = 20 - 10 \ \Rightarrow\ 10x = 10 \]
\[ \frac{10x}{10} = \frac{10}{10} \ \Rightarrow\ x = 1 \]
\[ 10\cdot1 + 10 = 10 + 10 = 20 \checkmark \]

Trying values of x in 10x + 10 = 20

x10x + 10Equals 20?
-10no
010no
120yes
230no
340no

Questions

What is x in 10x + 10 = 20?

The solution of 10x + 10 = 20 is x = 1.

How do you solve 10x + 10 = 20?

Subtract 10 from both sides to get 10x = 10, then divide both sides by 10 to get x = 1.

How do I check the answer?

Replace x by 1: 10(1) + 10 = 20, which is 20.

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