Solve 10x + 1 = 41
The solution of 10x + 1 = 41 is x = 4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = 4 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 1 = 41\ \Rightarrow\ x = 4 \]
\[ 10x + 1 = 41 \]
\[ 10x + 1 - 1 = 41 - 1 \ \Rightarrow\ 10x = 40 \]
\[ \frac{10x}{10} = \frac{40}{10} \ \Rightarrow\ x = 4 \]
\[ 10\cdot4 + 1 = 40 + 1 = 41 \checkmark \]Trying values of x in 10x + 1 = 41
| x | 10x + 1 | Equals 41? |
|---|---|---|
| 2 | 21 | no |
| 3 | 31 | no |
| 4 | 41 | yes |
| 5 | 51 | no |
| 6 | 61 | no |
Questions
What is x in 10x + 1 = 41?
The solution of 10x + 1 = 41 is x = 4.
How do you solve 10x + 1 = 41?
Subtract 1 from both sides to get 10x = 40, then divide both sides by 10 to get x = 4.
How do I check the answer?
Replace x by 4: 10(4) + 1 = 41, which is 41.