Solve 10x + 1 = 201
The solution of 10x + 1 = 201 is x = 20.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = 20 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 1 = 201\ \Rightarrow\ x = 20 \]
\[ 10x + 1 = 201 \]
\[ 10x + 1 - 1 = 201 - 1 \ \Rightarrow\ 10x = 200 \]
\[ \frac{10x}{10} = \frac{200}{10} \ \Rightarrow\ x = 20 \]
\[ 10\cdot20 + 1 = 200 + 1 = 201 \checkmark \]Trying values of x in 10x + 1 = 201
| x | 10x + 1 | Equals 201? |
|---|---|---|
| 18 | 181 | no |
| 19 | 191 | no |
| 20 | 201 | yes |
| 21 | 211 | no |
| 22 | 221 | no |
Questions
What is x in 10x + 1 = 201?
The solution of 10x + 1 = 201 is x = 20.
How do you solve 10x + 1 = 201?
Subtract 1 from both sides to get 10x = 200, then divide both sides by 10 to get x = 20.
How do I check the answer?
Replace x by 20: 10(20) + 1 = 201, which is 201.