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Solve 10x āˆ’ 9 = 41

The solution of 10x āˆ’ 9 = 41 is x = 5.

The lines y = 10x āˆ’ 9 and y = 41 meet at x = 5246810-2020406080100x = 5y = 10x āˆ’ 9y = 41
The lines y = 10x āˆ’ 9 and y = 41 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’9=4110x - 9 = 41
  2. 2

    Add 9 to both sides:

    10xāˆ’9+9=41+9 ⇒ 10x=5010x - 9 + 9 = 41 + 9 \ \Rightarrow\ 10x = 50
  3. 3

    Divide both sides by 10:

    10x10=5010 ⇒ x=5\frac{10x}{10} = \frac{50}{10} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    10ā‹…5āˆ’9=50āˆ’9=41āœ“10\cdot5 - 9 = 50 - 9 = 41 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 9 = 41\ \Rightarrow\ x = 5 \]
\[ 10x - 9 = 41 \]
\[ 10x - 9 + 9 = 41 + 9 \ \Rightarrow\ 10x = 50 \]
\[ \frac{10x}{10} = \frac{50}{10} \ \Rightarrow\ x = 5 \]
\[ 10\cdot5 - 9 = 50 - 9 = 41 \checkmark \]

Trying values of x in 10x āˆ’ 9 = 41

x10x āˆ’ 9Equals 41?
321no
431no
541yes
651no
761no

Questions

What is x in 10x āˆ’ 9 = 41?

The solution of 10x āˆ’ 9 = 41 is x = 5.

How do you solve 10x āˆ’ 9 = 41?

Add 9 to both sides to get 10x = 50, then divide both sides by 10 to get x = 5.

How do I check the answer?

Replace x by 5: 10(5) āˆ’ 9 = 41, which is 41.

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