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Solve 10x āˆ’ 8 = 32

The solution of 10x āˆ’ 8 = 32 is x = 4.

The lines y = 10x āˆ’ 8 and y = 32 meet at x = 4-2246810-40-2020406080100x = 4y = 10x āˆ’ 8y = 32
The lines y = 10x āˆ’ 8 and y = 32 meet at x = 4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’8=3210x - 8 = 32
  2. 2

    Add 8 to both sides:

    10xāˆ’8+8=32+8 ⇒ 10x=4010x - 8 + 8 = 32 + 8 \ \Rightarrow\ 10x = 40
  3. 3

    Divide both sides by 10:

    10x10=4010 ⇒ x=4\frac{10x}{10} = \frac{40}{10} \ \Rightarrow\ x = 4
  4. 4

    Check: put x = 4 back into the equation.

    10ā‹…4āˆ’8=40āˆ’8=32āœ“10\cdot4 - 8 = 40 - 8 = 32 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 8 = 32\ \Rightarrow\ x = 4 \]
\[ 10x - 8 = 32 \]
\[ 10x - 8 + 8 = 32 + 8 \ \Rightarrow\ 10x = 40 \]
\[ \frac{10x}{10} = \frac{40}{10} \ \Rightarrow\ x = 4 \]
\[ 10\cdot4 - 8 = 40 - 8 = 32 \checkmark \]

Trying values of x in 10x āˆ’ 8 = 32

x10x āˆ’ 8Equals 32?
212no
322no
432yes
542no
652no

Questions

What is x in 10x āˆ’ 8 = 32?

The solution of 10x āˆ’ 8 = 32 is x = 4.

How do you solve 10x āˆ’ 8 = 32?

Add 8 to both sides to get 10x = 40, then divide both sides by 10 to get x = 4.

How do I check the answer?

Replace x by 4: 10(4) āˆ’ 8 = 32, which is 32.

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