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Solve 10x āˆ’ 5 = āˆ’95

The solution of 10x āˆ’ 5 = āˆ’95 is x = -9.

The lines y = 10x āˆ’ 5 and y = -95 meet at x = -9-14-12-10-8-6-4-160-140-120-100-80-60-40x = -9y = 10x āˆ’ 5y = -95
The lines y = 10x āˆ’ 5 and y = -95 meet at x = -9. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’5=āˆ’9510x - 5 = -95
  2. 2

    Add 5 to both sides:

    10xāˆ’5+5=āˆ’95+5 ⇒ 10x=āˆ’9010x - 5 + 5 = -95 + 5 \ \Rightarrow\ 10x = -90
  3. 3

    Divide both sides by 10:

    10x10=āˆ’9010 ⇒ x=āˆ’9\frac{10x}{10} = \frac{-90}{10} \ \Rightarrow\ x = -9
  4. 4

    Check: put x = -9 back into the equation.

    10ā‹…(āˆ’9)āˆ’5=āˆ’90āˆ’5=āˆ’95āœ“10\cdot(-9) - 5 = -90 - 5 = -95 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 5 = -95\ \Rightarrow\ x = -9 \]
\[ 10x - 5 = -95 \]
\[ 10x - 5 + 5 = -95 + 5 \ \Rightarrow\ 10x = -90 \]
\[ \frac{10x}{10} = \frac{-90}{10} \ \Rightarrow\ x = -9 \]
\[ 10\cdot(-9) - 5 = -90 - 5 = -95 \checkmark \]

Trying values of x in 10x āˆ’ 5 = āˆ’95

x10x āˆ’ 5Equals -95?
-11-115no
-10-105no
-9-95yes
-8-85no
-7-75no

Questions

What is x in 10x āˆ’ 5 = āˆ’95?

The solution of 10x āˆ’ 5 = āˆ’95 is x = -9.

How do you solve 10x āˆ’ 5 = āˆ’95?

Add 5 to both sides to get 10x = -90, then divide both sides by 10 to get x = -9.

How do I check the answer?

Replace x by -9: 10(-9) āˆ’ 5 = -95, which is -95.

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    Solve 10x āˆ’ 5 = āˆ’95: x = -9 (steps and check) | WordGPT