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Solve 10x āˆ’ 5 = 15

The solution of 10x āˆ’ 5 = 15 is x = 2.

The lines y = 10x āˆ’ 5 and y = 15 meet at x = 2-4-22468-40-2020406080x = 2y = 10x āˆ’ 5y = 15
The lines y = 10x āˆ’ 5 and y = 15 meet at x = 2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’5=1510x - 5 = 15
  2. 2

    Add 5 to both sides:

    10xāˆ’5+5=15+5 ⇒ 10x=2010x - 5 + 5 = 15 + 5 \ \Rightarrow\ 10x = 20
  3. 3

    Divide both sides by 10:

    10x10=2010 ⇒ x=2\frac{10x}{10} = \frac{20}{10} \ \Rightarrow\ x = 2
  4. 4

    Check: put x = 2 back into the equation.

    10ā‹…2āˆ’5=20āˆ’5=15āœ“10\cdot2 - 5 = 20 - 5 = 15 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 5 = 15\ \Rightarrow\ x = 2 \]
\[ 10x - 5 = 15 \]
\[ 10x - 5 + 5 = 15 + 5 \ \Rightarrow\ 10x = 20 \]
\[ \frac{10x}{10} = \frac{20}{10} \ \Rightarrow\ x = 2 \]
\[ 10\cdot2 - 5 = 20 - 5 = 15 \checkmark \]

Trying values of x in 10x āˆ’ 5 = 15

x10x āˆ’ 5Equals 15?
0-5no
15no
215yes
325no
435no

Questions

What is x in 10x āˆ’ 5 = 15?

The solution of 10x āˆ’ 5 = 15 is x = 2.

How do you solve 10x āˆ’ 5 = 15?

Add 5 to both sides to get 10x = 20, then divide both sides by 10 to get x = 2.

How do I check the answer?

Replace x by 2: 10(2) āˆ’ 5 = 15, which is 15.

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