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Solve 10x āˆ’ 3 = 47

The solution of 10x āˆ’ 3 = 47 is x = 5.

The lines y = 10x āˆ’ 3 and y = 47 meet at x = 5246810-2020406080100x = 5y = 10x āˆ’ 3y = 47
The lines y = 10x āˆ’ 3 and y = 47 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’3=4710x - 3 = 47
  2. 2

    Add 3 to both sides:

    10xāˆ’3+3=47+3 ⇒ 10x=5010x - 3 + 3 = 47 + 3 \ \Rightarrow\ 10x = 50
  3. 3

    Divide both sides by 10:

    10x10=5010 ⇒ x=5\frac{10x}{10} = \frac{50}{10} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    10ā‹…5āˆ’3=50āˆ’3=47āœ“10\cdot5 - 3 = 50 - 3 = 47 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 3 = 47\ \Rightarrow\ x = 5 \]
\[ 10x - 3 = 47 \]
\[ 10x - 3 + 3 = 47 + 3 \ \Rightarrow\ 10x = 50 \]
\[ \frac{10x}{10} = \frac{50}{10} \ \Rightarrow\ x = 5 \]
\[ 10\cdot5 - 3 = 50 - 3 = 47 \checkmark \]

Trying values of x in 10x āˆ’ 3 = 47

x10x āˆ’ 3Equals 47?
327no
437no
547yes
657no
767no

Questions

What is x in 10x āˆ’ 3 = 47?

The solution of 10x āˆ’ 3 = 47 is x = 5.

How do you solve 10x āˆ’ 3 = 47?

Add 3 to both sides to get 10x = 50, then divide both sides by 10 to get x = 5.

How do I check the answer?

Replace x by 5: 10(5) āˆ’ 3 = 47, which is 47.

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