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Solve 10x āˆ’ 3 = 147

The solution of 10x āˆ’ 3 = 147 is x = 15.

The lines y = 10x āˆ’ 3 and y = 147 meet at x = 1510121416182080100120140160180200x = 15y = 10x āˆ’ 3y = 147
The lines y = 10x āˆ’ 3 and y = 147 meet at x = 15. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’3=14710x - 3 = 147
  2. 2

    Add 3 to both sides:

    10xāˆ’3+3=147+3 ⇒ 10x=15010x - 3 + 3 = 147 + 3 \ \Rightarrow\ 10x = 150
  3. 3

    Divide both sides by 10:

    10x10=15010 ⇒ x=15\frac{10x}{10} = \frac{150}{10} \ \Rightarrow\ x = 15
  4. 4

    Check: put x = 15 back into the equation.

    10ā‹…15āˆ’3=150āˆ’3=147āœ“10\cdot15 - 3 = 150 - 3 = 147 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 3 = 147\ \Rightarrow\ x = 15 \]
\[ 10x - 3 = 147 \]
\[ 10x - 3 + 3 = 147 + 3 \ \Rightarrow\ 10x = 150 \]
\[ \frac{10x}{10} = \frac{150}{10} \ \Rightarrow\ x = 15 \]
\[ 10\cdot15 - 3 = 150 - 3 = 147 \checkmark \]

Trying values of x in 10x āˆ’ 3 = 147

x10x āˆ’ 3Equals 147?
13127no
14137no
15147yes
16157no
17167no

Questions

What is x in 10x āˆ’ 3 = 147?

The solution of 10x āˆ’ 3 = 147 is x = 15.

How do you solve 10x āˆ’ 3 = 147?

Add 3 to both sides to get 10x = 150, then divide both sides by 10 to get x = 15.

How do I check the answer?

Replace x by 15: 10(15) āˆ’ 3 = 147, which is 147.

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