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Solve 10x āˆ’ 13 = 47

The solution of 10x āˆ’ 13 = 47 is x = 6.

The lines y = 10x āˆ’ 13 and y = 47 meet at x = 624681012-2020406080100x = 6y = 10x āˆ’ 13y = 47
The lines y = 10x āˆ’ 13 and y = 47 meet at x = 6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’13=4710x - 13 = 47
  2. 2

    Add 13 to both sides:

    10xāˆ’13+13=47+13 ⇒ 10x=6010x - 13 + 13 = 47 + 13 \ \Rightarrow\ 10x = 60
  3. 3

    Divide both sides by 10:

    10x10=6010 ⇒ x=6\frac{10x}{10} = \frac{60}{10} \ \Rightarrow\ x = 6
  4. 4

    Check: put x = 6 back into the equation.

    10ā‹…6āˆ’13=60āˆ’13=47āœ“10\cdot6 - 13 = 60 - 13 = 47 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 13 = 47\ \Rightarrow\ x = 6 \]
\[ 10x - 13 = 47 \]
\[ 10x - 13 + 13 = 47 + 13 \ \Rightarrow\ 10x = 60 \]
\[ \frac{10x}{10} = \frac{60}{10} \ \Rightarrow\ x = 6 \]
\[ 10\cdot6 - 13 = 60 - 13 = 47 \checkmark \]

Trying values of x in 10x āˆ’ 13 = 47

x10x āˆ’ 13Equals 47?
427no
537no
647yes
757no
867no

Questions

What is x in 10x āˆ’ 13 = 47?

The solution of 10x āˆ’ 13 = 47 is x = 6.

How do you solve 10x āˆ’ 13 = 47?

Add 13 to both sides to get 10x = 60, then divide both sides by 10 to get x = 6.

How do I check the answer?

Replace x by 6: 10(6) āˆ’ 13 = 47, which is 47.

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