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Solve 10x āˆ’ 12 = āˆ’12

The solution of 10x āˆ’ 12 = āˆ’12 is x = 0.

The lines y = 10x āˆ’ 12 and y = -12 meet at x = 0-6-4-2246-80-60-40-20204060x = 0y = 10x āˆ’ 12y = -12
The lines y = 10x āˆ’ 12 and y = -12 meet at x = 0. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’12=āˆ’1210x - 12 = -12
  2. 2

    Add 12 to both sides:

    10xāˆ’12+12=āˆ’12+12 ⇒ 10x=010x - 12 + 12 = -12 + 12 \ \Rightarrow\ 10x = 0
  3. 3

    Divide both sides by 10:

    10x10=010 ⇒ x=0\frac{10x}{10} = \frac{0}{10} \ \Rightarrow\ x = 0
  4. 4

    Check: put x = 0 back into the equation.

    10ā‹…0āˆ’12=0āˆ’12=āˆ’12āœ“10\cdot0 - 12 = 0 - 12 = -12 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 12 = -12\ \Rightarrow\ x = 0 \]
\[ 10x - 12 = -12 \]
\[ 10x - 12 + 12 = -12 + 12 \ \Rightarrow\ 10x = 0 \]
\[ \frac{10x}{10} = \frac{0}{10} \ \Rightarrow\ x = 0 \]
\[ 10\cdot0 - 12 = 0 - 12 = -12 \checkmark \]

Trying values of x in 10x āˆ’ 12 = āˆ’12

x10x āˆ’ 12Equals -12?
-2-32no
-1-22no
0-12yes
1-2no
28no

Questions

What is x in 10x āˆ’ 12 = āˆ’12?

The solution of 10x āˆ’ 12 = āˆ’12 is x = 0.

How do you solve 10x āˆ’ 12 = āˆ’12?

Add 12 to both sides to get 10x = 0, then divide both sides by 10 to get x = 0.

How do I check the answer?

Replace x by 0: 10(0) āˆ’ 12 = -12, which is -12.

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    Solve 10x āˆ’ 12 = āˆ’12: x = 0 (steps and check) | WordGPT