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Solve 10x āˆ’ 12 = 78

The solution of 10x āˆ’ 12 = 78 is x = 9.

The lines y = 10x āˆ’ 12 and y = 78 meet at x = 946810121420406080100120140x = 9y = 10x āˆ’ 12y = 78
The lines y = 10x āˆ’ 12 and y = 78 meet at x = 9. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’12=7810x - 12 = 78
  2. 2

    Add 12 to both sides:

    10xāˆ’12+12=78+12 ⇒ 10x=9010x - 12 + 12 = 78 + 12 \ \Rightarrow\ 10x = 90
  3. 3

    Divide both sides by 10:

    10x10=9010 ⇒ x=9\frac{10x}{10} = \frac{90}{10} \ \Rightarrow\ x = 9
  4. 4

    Check: put x = 9 back into the equation.

    10ā‹…9āˆ’12=90āˆ’12=78āœ“10\cdot9 - 12 = 90 - 12 = 78 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 12 = 78\ \Rightarrow\ x = 9 \]
\[ 10x - 12 = 78 \]
\[ 10x - 12 + 12 = 78 + 12 \ \Rightarrow\ 10x = 90 \]
\[ \frac{10x}{10} = \frac{90}{10} \ \Rightarrow\ x = 9 \]
\[ 10\cdot9 - 12 = 90 - 12 = 78 \checkmark \]

Trying values of x in 10x āˆ’ 12 = 78

x10x āˆ’ 12Equals 78?
758no
868no
978yes
1088no
1198no

Questions

What is x in 10x āˆ’ 12 = 78?

The solution of 10x āˆ’ 12 = 78 is x = 9.

How do you solve 10x āˆ’ 12 = 78?

Add 12 to both sides to get 10x = 90, then divide both sides by 10 to get x = 9.

How do I check the answer?

Replace x by 9: 10(9) āˆ’ 12 = 78, which is 78.

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