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Solve 10x āˆ’ 12 = 128

The solution of 10x āˆ’ 12 = 128 is x = 14.

The lines y = 10x āˆ’ 12 and y = 128 meet at x = 1481012141618206080100120140160180200x = 14y = 10x āˆ’ 12y = 128
The lines y = 10x āˆ’ 12 and y = 128 meet at x = 14. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’12=12810x - 12 = 128
  2. 2

    Add 12 to both sides:

    10xāˆ’12+12=128+12 ⇒ 10x=14010x - 12 + 12 = 128 + 12 \ \Rightarrow\ 10x = 140
  3. 3

    Divide both sides by 10:

    10x10=14010 ⇒ x=14\frac{10x}{10} = \frac{140}{10} \ \Rightarrow\ x = 14
  4. 4

    Check: put x = 14 back into the equation.

    10ā‹…14āˆ’12=140āˆ’12=128āœ“10\cdot14 - 12 = 140 - 12 = 128 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 12 = 128\ \Rightarrow\ x = 14 \]
\[ 10x - 12 = 128 \]
\[ 10x - 12 + 12 = 128 + 12 \ \Rightarrow\ 10x = 140 \]
\[ \frac{10x}{10} = \frac{140}{10} \ \Rightarrow\ x = 14 \]
\[ 10\cdot14 - 12 = 140 - 12 = 128 \checkmark \]

Trying values of x in 10x āˆ’ 12 = 128

x10x āˆ’ 12Equals 128?
12108no
13118no
14128yes
15138no
16148no

Questions

What is x in 10x āˆ’ 12 = 128?

The solution of 10x āˆ’ 12 = 128 is x = 14.

How do you solve 10x āˆ’ 12 = 128?

Add 12 to both sides to get 10x = 140, then divide both sides by 10 to get x = 14.

How do I check the answer?

Replace x by 14: 10(14) āˆ’ 12 = 128, which is 128.

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