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Solve 10x āˆ’ 11 = 109

The solution of 10x āˆ’ 11 = 109 is x = 12.

The lines y = 10x āˆ’ 11 and y = 109 meet at x = 12681012141618406080100120140160180x = 12y = 10x āˆ’ 11y = 109
The lines y = 10x āˆ’ 11 and y = 109 meet at x = 12. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’11=10910x - 11 = 109
  2. 2

    Add 11 to both sides:

    10xāˆ’11+11=109+11 ⇒ 10x=12010x - 11 + 11 = 109 + 11 \ \Rightarrow\ 10x = 120
  3. 3

    Divide both sides by 10:

    10x10=12010 ⇒ x=12\frac{10x}{10} = \frac{120}{10} \ \Rightarrow\ x = 12
  4. 4

    Check: put x = 12 back into the equation.

    10ā‹…12āˆ’11=120āˆ’11=109āœ“10\cdot12 - 11 = 120 - 11 = 109 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 11 = 109\ \Rightarrow\ x = 12 \]
\[ 10x - 11 = 109 \]
\[ 10x - 11 + 11 = 109 + 11 \ \Rightarrow\ 10x = 120 \]
\[ \frac{10x}{10} = \frac{120}{10} \ \Rightarrow\ x = 12 \]
\[ 10\cdot12 - 11 = 120 - 11 = 109 \checkmark \]

Trying values of x in 10x āˆ’ 11 = 109

x10x āˆ’ 11Equals 109?
1089no
1199no
12109yes
13119no
14129no

Questions

What is x in 10x āˆ’ 11 = 109?

The solution of 10x āˆ’ 11 = 109 is x = 12.

How do you solve 10x āˆ’ 11 = 109?

Add 11 to both sides to get 10x = 120, then divide both sides by 10 to get x = 12.

How do I check the answer?

Replace x by 12: 10(12) āˆ’ 11 = 109, which is 109.

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