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Solve 10x āˆ’ 10 = āˆ’110

The solution of 10x āˆ’ 10 = āˆ’110 is x = -10.

The lines y = 10x āˆ’ 10 and y = -110 meet at x = -10-16-14-12-10-8-6-4-180-160-140-120-100-80-60-40x = -10y = 10x āˆ’ 10y = -110
The lines y = 10x āˆ’ 10 and y = -110 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’10=āˆ’11010x - 10 = -110
  2. 2

    Add 10 to both sides:

    10xāˆ’10+10=āˆ’110+10 ⇒ 10x=āˆ’10010x - 10 + 10 = -110 + 10 \ \Rightarrow\ 10x = -100
  3. 3

    Divide both sides by 10:

    10x10=āˆ’10010 ⇒ x=āˆ’10\frac{10x}{10} = \frac{-100}{10} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    10ā‹…(āˆ’10)āˆ’10=āˆ’100āˆ’10=āˆ’110āœ“10\cdot(-10) - 10 = -100 - 10 = -110 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 10 = -110\ \Rightarrow\ x = -10 \]
\[ 10x - 10 = -110 \]
\[ 10x - 10 + 10 = -110 + 10 \ \Rightarrow\ 10x = -100 \]
\[ \frac{10x}{10} = \frac{-100}{10} \ \Rightarrow\ x = -10 \]
\[ 10\cdot(-10) - 10 = -100 - 10 = -110 \checkmark \]

Trying values of x in 10x āˆ’ 10 = āˆ’110

x10x āˆ’ 10Equals -110?
-12-130no
-11-120no
-10-110yes
-9-100no
-8-90no

Questions

What is x in 10x āˆ’ 10 = āˆ’110?

The solution of 10x āˆ’ 10 = āˆ’110 is x = -10.

How do you solve 10x āˆ’ 10 = āˆ’110?

Add 10 to both sides to get 10x = -100, then divide both sides by 10 to get x = -10.

How do I check the answer?

Replace x by -10: 10(-10) āˆ’ 10 = -110, which is -110.

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