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Solve 10x āˆ’ 10 = 40

The solution of 10x āˆ’ 10 = 40 is x = 5.

The lines y = 10x āˆ’ 10 and y = 40 meet at x = 5246810-2020406080100x = 5y = 10x āˆ’ 10y = 40
The lines y = 10x āˆ’ 10 and y = 40 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’10=4010x - 10 = 40
  2. 2

    Add 10 to both sides:

    10xāˆ’10+10=40+10 ⇒ 10x=5010x - 10 + 10 = 40 + 10 \ \Rightarrow\ 10x = 50
  3. 3

    Divide both sides by 10:

    10x10=5010 ⇒ x=5\frac{10x}{10} = \frac{50}{10} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    10ā‹…5āˆ’10=50āˆ’10=40āœ“10\cdot5 - 10 = 50 - 10 = 40 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 10 = 40\ \Rightarrow\ x = 5 \]
\[ 10x - 10 = 40 \]
\[ 10x - 10 + 10 = 40 + 10 \ \Rightarrow\ 10x = 50 \]
\[ \frac{10x}{10} = \frac{50}{10} \ \Rightarrow\ x = 5 \]
\[ 10\cdot5 - 10 = 50 - 10 = 40 \checkmark \]

Trying values of x in 10x āˆ’ 10 = 40

x10x āˆ’ 10Equals 40?
320no
430no
540yes
650no
760no

Questions

What is x in 10x āˆ’ 10 = 40?

The solution of 10x āˆ’ 10 = 40 is x = 5.

How do you solve 10x āˆ’ 10 = 40?

Add 10 to both sides to get 10x = 50, then divide both sides by 10 to get x = 5.

How do I check the answer?

Replace x by 5: 10(5) āˆ’ 10 = 40, which is 40.

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