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Solve 10x āˆ’ 10 = 20

The solution of 10x āˆ’ 10 = 20 is x = 3.

The lines y = 10x āˆ’ 10 and y = 20 meet at x = 3-22468-40-2020406080x = 3y = 10x āˆ’ 10y = 20
The lines y = 10x āˆ’ 10 and y = 20 meet at x = 3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’10=2010x - 10 = 20
  2. 2

    Add 10 to both sides:

    10xāˆ’10+10=20+10 ⇒ 10x=3010x - 10 + 10 = 20 + 10 \ \Rightarrow\ 10x = 30
  3. 3

    Divide both sides by 10:

    10x10=3010 ⇒ x=3\frac{10x}{10} = \frac{30}{10} \ \Rightarrow\ x = 3
  4. 4

    Check: put x = 3 back into the equation.

    10ā‹…3āˆ’10=30āˆ’10=20āœ“10\cdot3 - 10 = 30 - 10 = 20 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 10 = 20\ \Rightarrow\ x = 3 \]
\[ 10x - 10 = 20 \]
\[ 10x - 10 + 10 = 20 + 10 \ \Rightarrow\ 10x = 30 \]
\[ \frac{10x}{10} = \frac{30}{10} \ \Rightarrow\ x = 3 \]
\[ 10\cdot3 - 10 = 30 - 10 = 20 \checkmark \]

Trying values of x in 10x āˆ’ 10 = 20

x10x āˆ’ 10Equals 20?
10no
210no
320yes
430no
540no

Questions

What is x in 10x āˆ’ 10 = 20?

The solution of 10x āˆ’ 10 = 20 is x = 3.

How do you solve 10x āˆ’ 10 = 20?

Add 10 to both sides to get 10x = 30, then divide both sides by 10 to get x = 3.

How do I check the answer?

Replace x by 3: 10(3) āˆ’ 10 = 20, which is 20.

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