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Integral of x2x^{2}

The integral of x2x^{2} is x33+C\frac{x^{3}}{3} + C.

Graph of f(x) = x^2 with the area from 0 to 1 shaded-0.4-0.20.20.40.60.811.21.41.60.511.522.5f(x)
Graph of f(x) = x^2 with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 0.33333333.

How to work it out

  1. 1

    We want an antiderivative of f(x) = x2x^{2}.

    ∫x2 dx\int x^{2}\,dx
  2. 2

    Method: power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1).

  3. 3

    That gives the antiderivative; add the constant C because any constant disappears when you differentiate:

    ∫x2 dx=x33+C\int x^{2}\,dx = \frac{x^{3}}{3} + C
  4. 4

    Check by differentiating the answer; you must get the original function back:

    ddx[x33]=9x29\frac{d}{dx}\left[\frac{x^{3}}{3}\right] = \frac{9 x^{2}}{9}
  5. 5

    As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:

    ∫01x2 dx=[x33]01≈0.33333333\int_{0}^{1} x^{2}\,dx = \Big[\frac{x^{3}}{3}\Big]_{0}^{1} \approx 0.33333333
LaTeX source of the formulas on this page
\[ \int x^{2}\,dx = \frac{x^{3}}{3} + C \]
\[ \int x^{2}\,dx \]
\[ \frac{d}{dx}\left[\frac{x^{3}}{3}\right] = \frac{9 x^{2}}{9} \]
\[ \int_{0}^{1} x^{2}\,dx = \Big[\frac{x^{3}}{3}\Big]_{0}^{1} \approx 0.33333333 \]

Definite integrals of the same function

IntervalValue
from 0 to 10.33333333
from 0 to 0.50.041666667

Questions

What is the integral of x2x^{2}?

The integral of x2x^{2} is x33+C\frac{x^{3}}{3} + C.

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of x2x^{2} from 0 to 1?

About 0.33333333.

More integrals

    Integral of x^2: x^3 / 3 + C (with steps) | WordGPT