Integral of $x^{12}$

Q: What is the integral of x^12?

The integral of x^12 is x^1313 + C.

The integral of $x^{12}$ is $\frac{x^{13}}{13} + C$ .

\int x^{12}\,dx = \frac{x^{13}}{13} + C

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Graph of f(x) = x^12 with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 0.076923077.

How to work it out

1
We want an antiderivative of f(x) = $x^{12}$ .
$\int x^{12}\,dx$
2
Method: power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1).
3
That gives the antiderivative; add the constant C because any constant disappears when you differentiate:
$\int x^{12}\,dx = \frac{x^{13}}{13} + C$
4
Check by differentiating the answer; you must get the original function back:
$\frac{d}{dx}\left[\frac{x^{13}}{13}\right] = \frac{169 x^{12}}{169}$
5
As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:
$\int_{0}^{1} x^{12}\,dx = \Big[\frac{x^{13}}{13}\Big]_{0}^{1} \approx 0.076923077$

LaTeX source of the formulas on this page

\[ \int x^{12}\,dx = \frac{x^{13}}{13} + C \]
\[ \int x^{12}\,dx \]
\[ \frac{d}{dx}\left[\frac{x^{13}}{13}\right] = \frac{169 x^{12}}{169} \]
\[ \int_{0}^{1} x^{12}\,dx = \Big[\frac{x^{13}}{13}\Big]_{0}^{1} \approx 0.076923077 \]

Definite integrals of the same function

Interval	Value
from 0 to 1	0.076923077
from 0 to 0.5	0.000009390024

Questions

What is the integral of

x^{12}

The integral of $x^{12}$ is $\frac{x^{13}}{13} + C$ .

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of

x^{12}

from 0 to 1?

About 0.076923077.

Integral of x12x^{12}x12

How to work it out

Definite integrals of the same function

Questions

More integrals

Integral of $x^{12}$