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Integral of e8xe^{8 x}

The integral of e8xe^{8 x} is e8x8+C\frac{e^{8 x}}{8} + C.

Graph of f(x) = exp(8x) with the area from 0 to 1 shaded-0.4-0.20.20.40.60.811.21.41.6500001e+52e+52e+53e+5f(x)
Graph of f(x) = exp(8x) with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 372.49475.

How to work it out

  1. 1

    We want an antiderivative of f(x) = exp(8x).

    ∫e8x dx\int e^{8 x}\,dx
  2. 2

    Method: ∫ekxe^{kx} dx = ekxe^{kx}/k.

  3. 3

    That gives the antiderivative; add the constant C because any constant disappears when you differentiate:

    ∫e8x dx=e8x8+C\int e^{8 x}\,dx = \frac{e^{8 x}}{8} + C
  4. 4

    Check by differentiating the answer; you must get the original function back:

    ddx[e8x8]=64e8x64\frac{d}{dx}\left[\frac{e^{8 x}}{8}\right] = \frac{64 e^{8 x}}{64}
  5. 5

    As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:

    ∫01e8x dx=[e8x8]01ā‰ˆ372.49475\int_{0}^{1} e^{8 x}\,dx = \Big[\frac{e^{8 x}}{8}\Big]_{0}^{1} \approx 372.49475
LaTeX source of the formulas on this page
\[ \int e^{8 x}\,dx = \frac{e^{8 x}}{8} + C \]
\[ \int e^{8 x}\,dx \]
\[ \frac{d}{dx}\left[\frac{e^{8 x}}{8}\right] = \frac{64 e^{8 x}}{64} \]
\[ \int_{0}^{1} e^{8 x}\,dx = \Big[\frac{e^{8 x}}{8}\Big]_{0}^{1} \approx 372.49475 \]

Definite integrals of the same function

IntervalValue
from 0 to 1372.49475
from 0 to 0.56.6997688

Questions

What is the integral of exp(8x)?

The integral of e8xe^{8 x} is e8x8+C\frac{e^{8 x}}{8} + C.

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of exp(8x) from 0 to 1?

About 372.49475.

More integrals

    Integral of exp(8x): exp(8x) / 8 + C (with steps) | WordGPT