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Integral of e5xe^{5 x}

The integral of e5xe^{5 x} is e5x5+C\frac{e^{5 x}}{5} + C.

Graph of f(x) = exp(5x) with the area from 0 to 1 shaded-0.4-0.20.20.40.60.811.21.41.65001000150020002500f(x)
Graph of f(x) = exp(5x) with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 29.482632.

How to work it out

  1. 1

    We want an antiderivative of f(x) = exp(5x).

    ∫e5x dx\int e^{5 x}\,dx
  2. 2

    Method: ∫ekxe^{kx} dx = ekxe^{kx}/k.

  3. 3

    That gives the antiderivative; add the constant C because any constant disappears when you differentiate:

    ∫e5x dx=e5x5+C\int e^{5 x}\,dx = \frac{e^{5 x}}{5} + C
  4. 4

    Check by differentiating the answer; you must get the original function back:

    ddx[e5x5]=25e5x25\frac{d}{dx}\left[\frac{e^{5 x}}{5}\right] = \frac{25 e^{5 x}}{25}
  5. 5

    As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:

    ∫01e5x dx=[e5x5]01ā‰ˆ29.482632\int_{0}^{1} e^{5 x}\,dx = \Big[\frac{e^{5 x}}{5}\Big]_{0}^{1} \approx 29.482632
LaTeX source of the formulas on this page
\[ \int e^{5 x}\,dx = \frac{e^{5 x}}{5} + C \]
\[ \int e^{5 x}\,dx \]
\[ \frac{d}{dx}\left[\frac{e^{5 x}}{5}\right] = \frac{25 e^{5 x}}{25} \]
\[ \int_{0}^{1} e^{5 x}\,dx = \Big[\frac{e^{5 x}}{5}\Big]_{0}^{1} \approx 29.482632 \]

Definite integrals of the same function

IntervalValue
from 0 to 129.482632
from 0 to 0.52.2364988

Questions

What is the integral of exp(5x)?

The integral of e5xe^{5 x} is e5x5+C\frac{e^{5 x}}{5} + C.

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of exp(5x) from 0 to 1?

About 29.482632.

More integrals

    Integral of exp(5x): exp(5x) / 5 + C (with steps) | WordGPT