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Integral of e4xe^{4 x}

The integral of e4xe^{4 x} is e4x4+C\frac{e^{4 x}}{4} + C.

Graph of f(x) = exp(4x) with the area from 0 to 1 shaded-0.4-0.20.20.40.60.811.21.41.6100200300400500f(x)
Graph of f(x) = exp(4x) with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 13.399538.

How to work it out

  1. 1

    We want an antiderivative of f(x) = exp(4x).

    ∫e4x dx\int e^{4 x}\,dx
  2. 2

    Method: ∫ekxe^{kx} dx = ekxe^{kx}/k.

  3. 3

    That gives the antiderivative; add the constant C because any constant disappears when you differentiate:

    ∫e4x dx=e4x4+C\int e^{4 x}\,dx = \frac{e^{4 x}}{4} + C
  4. 4

    Check by differentiating the answer; you must get the original function back:

    ddx[e4x4]=16e4x16\frac{d}{dx}\left[\frac{e^{4 x}}{4}\right] = \frac{16 e^{4 x}}{16}
  5. 5

    As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:

    ∫01e4x dx=[e4x4]01ā‰ˆ13.399538\int_{0}^{1} e^{4 x}\,dx = \Big[\frac{e^{4 x}}{4}\Big]_{0}^{1} \approx 13.399538
LaTeX source of the formulas on this page
\[ \int e^{4 x}\,dx = \frac{e^{4 x}}{4} + C \]
\[ \int e^{4 x}\,dx \]
\[ \frac{d}{dx}\left[\frac{e^{4 x}}{4}\right] = \frac{16 e^{4 x}}{16} \]
\[ \int_{0}^{1} e^{4 x}\,dx = \Big[\frac{e^{4 x}}{4}\Big]_{0}^{1} \approx 13.399538 \]

Definite integrals of the same function

IntervalValue
from 0 to 113.399538
from 0 to 0.51.597264

Questions

What is the integral of exp(4x)?

The integral of e4xe^{4 x} is e4x4+C\frac{e^{4 x}}{4} + C.

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of exp(4x) from 0 to 1?

About 13.399538.

More integrals

    Integral of exp(4x): exp(4x) / 4 + C (with steps) | WordGPT