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Integral of 7x47 x^{4}

The integral of 7x47 x^{4} is 7x55+C\frac{7 x^{5}}{5} + C.

Graph of f(x) = 7 * x^4 with the area from 0 to 1 shaded-0.4-0.20.20.40.60.811.21.41.610203040f(x)
Graph of f(x) = 7 * x^4 with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 1.4.

How to work it out

  1. 1

    We want an antiderivative of f(x) = 7 * x4x^{4}.

    ∫7x4 dx\int 7 x^{4}\,dx
  2. 2

    Method: constant multiple and power rule.

  3. 3

    That gives the antiderivative; add the constant C because any constant disappears when you differentiate:

    ∫7x4 dx=7x55+C\int 7 x^{4}\,dx = \frac{7 x^{5}}{5} + C
  4. 4

    Check by differentiating the answer; you must get the original function back:

    ddx[7x55]=175x425\frac{d}{dx}\left[\frac{7 x^{5}}{5}\right] = \frac{175 x^{4}}{25}
  5. 5

    As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:

    ∫017x4 dx=[7x55]01ā‰ˆ1.4\int_{0}^{1} 7 x^{4}\,dx = \Big[\frac{7 x^{5}}{5}\Big]_{0}^{1} \approx 1.4
LaTeX source of the formulas on this page
\[ \int 7 x^{4}\,dx = \frac{7 x^{5}}{5} + C \]
\[ \int 7 x^{4}\,dx \]
\[ \frac{d}{dx}\left[\frac{7 x^{5}}{5}\right] = \frac{175 x^{4}}{25} \]
\[ \int_{0}^{1} 7 x^{4}\,dx = \Big[\frac{7 x^{5}}{5}\Big]_{0}^{1} \approx 1.4 \]

Definite integrals of the same function

IntervalValue
from 0 to 11.4
from 0 to 0.50.04375

Questions

What is the integral of 7 * x4x^{4}?

The integral of 7x47 x^{4} is 7x55+C\frac{7 x^{5}}{5} + C.

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of 7 * x4x^{4} from 0 to 1?

About 1.4.

More integrals

    Integral of 7 * x^4: 7 * x^5 / 5 + C (with steps) | WordGPT