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Integral of 3x43 x^{4}

The integral of 3x43 x^{4} is 3x55+C\frac{3 x^{5}}{5} + C.

Graph of f(x) = 3 * x^4 with the area from 0 to 1 shaded-0.4-0.20.20.40.60.811.21.41.651015f(x)
Graph of f(x) = 3 * x^4 with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 0.6.

How to work it out

  1. 1

    We want an antiderivative of f(x) = 3 * x4x^{4}.

    ∫3x4 dx\int 3 x^{4}\,dx
  2. 2

    Method: constant multiple and power rule.

  3. 3

    That gives the antiderivative; add the constant C because any constant disappears when you differentiate:

    ∫3x4 dx=3x55+C\int 3 x^{4}\,dx = \frac{3 x^{5}}{5} + C
  4. 4

    Check by differentiating the answer; you must get the original function back:

    ddx[3x55]=75x425\frac{d}{dx}\left[\frac{3 x^{5}}{5}\right] = \frac{75 x^{4}}{25}
  5. 5

    As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:

    ∫013x4 dx=[3x55]01ā‰ˆ0.6\int_{0}^{1} 3 x^{4}\,dx = \Big[\frac{3 x^{5}}{5}\Big]_{0}^{1} \approx 0.6
LaTeX source of the formulas on this page
\[ \int 3 x^{4}\,dx = \frac{3 x^{5}}{5} + C \]
\[ \int 3 x^{4}\,dx \]
\[ \frac{d}{dx}\left[\frac{3 x^{5}}{5}\right] = \frac{75 x^{4}}{25} \]
\[ \int_{0}^{1} 3 x^{4}\,dx = \Big[\frac{3 x^{5}}{5}\Big]_{0}^{1} \approx 0.6 \]

Definite integrals of the same function

IntervalValue
from 0 to 10.6
from 0 to 0.50.01875

Questions

What is the integral of 3 * x4x^{4}?

The integral of 3x43 x^{4} is 3x55+C\frac{3 x^{5}}{5} + C.

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of 3 * x4x^{4} from 0 to 1?

About 0.6.

More integrals

    Integral of 3 * x^4: 3 * x^5 / 5 + C (with steps) | WordGPT