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Integral of 3x33 x^{3}

The integral of 3x33 x^{3} is 3x44+C\frac{3 x^{4}}{4} + C.

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Graph of f(x) = 3 * x^3 with the area from 0 to 1 shaded-0.4-0.20.20.40.60.811.21.41.6-224681012f(x)
Graph of f(x) = 3 * x^3 with the area from 0 to 1 shaded. The shaded area equals the definite integral, about 0.75.

How to work it out

  1. 1

    We want an antiderivative of f(x) = 3 * x3x^{3}.

    āˆ«3x3ā€‰dx\int 3 x^{3}\,dx
  2. 2

    Method: constant multiple and power rule.

  3. 3

    That gives the antiderivative; add the constant C because any constant disappears when you differentiate:

    āˆ«3x3ā€‰dx=3x44+C\int 3 x^{3}\,dx = \frac{3 x^{4}}{4} + C
  4. 4

    Check by differentiating the answer; you must get the original function back:

    ddx[3x44]=48x316\frac{d}{dx}\left[\frac{3 x^{4}}{4}\right] = \frac{48 x^{3}}{16}
  5. 5

    As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:

    āˆ«013x3ā€‰dx=[3x44]01ā‰ˆ0.75\int_{0}^{1} 3 x^{3}\,dx = \Big[\frac{3 x^{4}}{4}\Big]_{0}^{1} \approx 0.75
LaTeX source of the formulas on this page
\[ \int 3 x^{3}\,dx = \frac{3 x^{4}}{4} + C \]
\[ \int 3 x^{3}\,dx \]
\[ \frac{d}{dx}\left[\frac{3 x^{4}}{4}\right] = \frac{48 x^{3}}{16} \]
\[ \int_{0}^{1} 3 x^{3}\,dx = \Big[\frac{3 x^{4}}{4}\Big]_{0}^{1} \approx 0.75 \]

Definite integrals of the same function

IntervalValue
from 0 to 10.75
from 0 to 0.50.046875

Questions

What is the integral of 3 * x3x^{3}?

The integral of 3x33 x^{3} is 3x44+C\frac{3 x^{4}}{4} + C.

Why do we add + C?

Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.

What is the integral of 3 * x3x^{3} from 0 to 1?

About 0.75.

More integrals

    Integral of 3 * x^3: 3 * x^4 / 4 + C (with steps) | WordGPT