Derivative of
The derivative of is .
f(x) =
Type any function of x; the derivative is computed symbolically in your browser.
How to work it out
- 1
We differentiate with respect to x. The rule that applies is the quotient rule.
- 2
Quotient rule: . Let and .
- 3
Differentiate each piece:
- 4
Put them in the rule:
- 5
Simplify:
- 6
Differentiating once more gives the second derivative, which tells you about curvature:
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[\frac{x^{4}}{\sin\left(x\right)}\right] = \frac{4 x^{3} \sin\left(x\right) - x^{4} \cos\left(x\right)}{\sin\left(x\right)^{2}} \]
\[ f(x) = \frac{x^{4}}{\sin\left(x\right)} \]
\[ u = x^{4},\quad v = \sin\left(x\right) \]
\[ u' = 4 x^{3},\quad v' = \cos\left(x\right) \]
\[ f'(x) = \frac{\left(4 x^{3}\right)\left(\sin\left(x\right)\right) - \left(x^{4}\right)\left(\cos\left(x\right)\right)}{\left(\sin\left(x\right)\right)^{2}} \]
\[ f'(x) = \frac{4 x^{3} \sin\left(x\right) - x^{4} \cos\left(x\right)}{\sin\left(x\right)^{2}} \]
\[ f''(x) = \frac{\left(12 x^{2} \sin\left(x\right) + 4 x^{3} \cos\left(x\right) - \left(4 x^{3} \cos\left(x\right) + x^{4} -\sin\left(x\right)\right)\right) \sin\left(x\right)^{2} - \left(4 x^{3} \sin\left(x\right) - x^{4} \cos\left(x\right)\right) 2 \sin\left(x\right) \cos\left(x\right)}{\left(\sin\left(x\right)^{2}\right)^{2}} \]Values of f and f' for / sin(x)
| x | f(x) | f'(x) |
|---|---|---|
| -2 | -17.596003 | 43.244949 |
| -1 | -1.1883951 | 3.9905207 |
| 0.5 | 0.13036435 | 0.80428447 |
| 1 | 1.1883951 | 3.9905207 |
| 2 | 17.596003 | 43.244949 |
| 3 | 573.97956 | 4791.9176 |
Questions
What is the derivative of / sin(x)?
The derivative of is .
What is the second derivative of / sin(x)?
((12 * * sin(x) + 4 * * cos(x) - (4 * * cos(x) + * -sin(x))) * sin(x)^2 - (4 * * sin(x) - * cos(x)) * 2sin(x) * cos(x)) / (sin(x)^2)^2.
Which rule do you use for / sin(x)?
The quotient rule.
What is the slope of / sin(x) at x = 1?
3.9905207.