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Derivative of x3tan⁡(x)x^{3} \tan\left(x\right)

The derivative of x3tan⁡(x)x^{3} \tan\left(x\right) is 3x2tan⁡(x)+x31cos⁡(x)23 x^{2} \tan\left(x\right) + x^{3} \frac{1}{\cos\left(x\right)^{2}}.

f(x) =
ddx[x3tan⁡(x)]=3x2tan⁡(x)+x31cos⁡(x)2\frac{d}{dx}\left[x^{3} \tan\left(x\right)\right] = 3 x^{2} \tan\left(x\right) + x^{3} \frac{1}{\cos\left(x\right)^{2}}

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Graph of f(x) = x^3 * tan(x) and its derivative-3-2-1123-100-80-60-40-2020406080slope 8.098f(x)f'(x)tangent at x = 1
Graph of f(x) = x^3 * tan(x) and its derivative. The dashed line is the tangent at x = 1; its slope is f'(1) = 8.0977.

How to work it out

  1. 1

    We differentiate f(x)=x3tan⁡(x)f(x) = x^{3} \tan\left(x\right) with respect to x. The rule that applies is the product rule.

    f(x)=x3tan⁡(x)f(x) = x^{3} \tan\left(x\right)
  2. 2

    Product rule: (uv)′=u′v+uv′(uv)' = u'v + uv'. Let u=x3u = x^{3} and v=tan⁡(x)v = \tan\left(x\right).

    u=x3,v=tan⁡(x)u = x^{3},\quad v = \tan\left(x\right)
  3. 3

    Differentiate each piece:

    u′=3x2,v′=1cos⁡(x)2u' = 3 x^{2},\quad v' = \frac{1}{\cos\left(x\right)^{2}}
  4. 4

    Put them in the rule:

    f′(x)=(3x2)(tan⁡(x))+(x3)(1cos⁡(x)2)f'(x) = \left(3 x^{2}\right)\left(\tan\left(x\right)\right) + \left(x^{3}\right)\left(\frac{1}{\cos\left(x\right)^{2}}\right)
  5. 5

    Simplify:

    f′(x)=3x2tan⁡(x)+x31cos⁡(x)2f'(x) = 3 x^{2} \tan\left(x\right) + x^{3} \frac{1}{\cos\left(x\right)^{2}}
  6. 6

    Differentiating once more gives the second derivative, which tells you about curvature:

    f′′(x)=6xtan⁡(x)+3x21cos⁡(x)2+3x21cos⁡(x)2+x3−(2cos⁡(x)−sin⁡(x))(cos⁡(x)2)2f''(x) = 6 x \tan\left(x\right) + 3 x^{2} \frac{1}{\cos\left(x\right)^{2}} + 3 x^{2} \frac{1}{\cos\left(x\right)^{2}} + x^{3} \frac{-\left(2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\cos\left(x\right)^{2}\right)^{2}}
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[x^{3} \tan\left(x\right)\right] = 3 x^{2} \tan\left(x\right) + x^{3} \frac{1}{\cos\left(x\right)^{2}} \]
\[ f(x) = x^{3} \tan\left(x\right) \]
\[ u = x^{3},\quad v = \tan\left(x\right) \]
\[ u' = 3 x^{2},\quad v' = \frac{1}{\cos\left(x\right)^{2}} \]
\[ f'(x) = \left(3 x^{2}\right)\left(\tan\left(x\right)\right) + \left(x^{3}\right)\left(\frac{1}{\cos\left(x\right)^{2}}\right) \]
\[ f'(x) = 3 x^{2} \tan\left(x\right) + x^{3} \frac{1}{\cos\left(x\right)^{2}} \]
\[ f''(x) = 6 x \tan\left(x\right) + 3 x^{2} \frac{1}{\cos\left(x\right)^{2}} + 3 x^{2} \frac{1}{\cos\left(x\right)^{2}} + x^{3} \frac{-\left(2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\cos\left(x\right)^{2}\right)^{2}} \]

Values of f and f' for x3x^{3} * tan(x)

xf(x)f'(x)
-2-17.480319-19.974715
-11.5574077-8.097742
0.50.0682878110.57203267
11.55740778.097742
2-17.48031919.974715
3-3.848756723.69987

Questions

What is the derivative of x3x^{3} * tan(x)?

The derivative of x3tan⁡(x)x^{3} \tan\left(x\right) is 3x2tan⁡(x)+x31cos⁡(x)23 x^{2} \tan\left(x\right) + x^{3} \frac{1}{\cos\left(x\right)^{2}}.

What is the second derivative of x3x^{3} * tan(x)?

6x * tan(x) + 3 * x2x^{2} * 1 / cos(x)^2 + 3 * x2x^{2} * 1 / cos(x)^2 + x3x^{3} * -(2cos(x) * -sin(x)) / (cos(x)^2)^2.

Which rule do you use for x3x^{3} * tan(x)?

The product rule.

What is the slope of x3x^{3} * tan(x) at x = 1?

8.097742.

Related derivatives

    Derivative of x^3 * tan(x): 3 * x^2 * tan(x) + x^3 * 1 / cos(x)^2 (with steps) | WordGPT