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Derivative of x3x5\frac{x^{3}}{x^{5}}

The derivative of x3x5\frac{x^{3}}{x^{5}} is 3x2x5−x35x4(x5)2\frac{3 x^{2} x^{5} - x^{3} 5 x^{4}}{\left(x^{5}\right)^{2}}.

f(x) =
ddx[x3x5]=3x2x5−x35x4(x5)2\frac{d}{dx}\left[\frac{x^{3}}{x^{5}}\right] = \frac{3 x^{2} x^{5} - x^{3} 5 x^{4}}{\left(x^{5}\right)^{2}}

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Graph of f(x) = x^3 / x^5 and its derivative-3-2-1123-2020406080slope -2f(x)f'(x)tangent at x = 1
Graph of f(x) = x^3 / x^5 and its derivative. The dashed line is the tangent at x = 1; its slope is f'(1) = -2.

How to work it out

  1. 1

    We differentiate f(x)=x3x5f(x) = \frac{x^{3}}{x^{5}} with respect to x. The rule that applies is the quotient rule.

    f(x)=x3x5f(x) = \frac{x^{3}}{x^{5}}
  2. 2

    Quotient rule: (uv)′=u′v−uv′v2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^{2}}. Let u=x3u = x^{3} and v=x5v = x^{5}.

    u=x3,v=x5u = x^{3},\quad v = x^{5}
  3. 3

    Differentiate each piece:

    u′=3x2,v′=5x4u' = 3 x^{2},\quad v' = 5 x^{4}
  4. 4

    Put them in the rule:

    f′(x)=(3x2)(x5)−(x3)(5x4)(x5)2f'(x) = \frac{\left(3 x^{2}\right)\left(x^{5}\right) - \left(x^{3}\right)\left(5 x^{4}\right)}{\left(x^{5}\right)^{2}}
  5. 5

    Simplify:

    f′(x)=3x2x5−x35x4(x5)2f'(x) = \frac{3 x^{2} x^{5} - x^{3} 5 x^{4}}{\left(x^{5}\right)^{2}}
  6. 6

    Differentiating once more gives the second derivative, which tells you about curvature:

    f′′(x)=(6xx5+3x25x4−(3x25x4+x320x3))(x5)2−(3x2x5−x35x4)2x55x4((x5)2)2f''(x) = \frac{\left(6 x x^{5} + 3 x^{2} 5 x^{4} - \left(3 x^{2} 5 x^{4} + x^{3} 20 x^{3}\right)\right) \left(x^{5}\right)^{2} - \left(3 x^{2} x^{5} - x^{3} 5 x^{4}\right) 2 x^{5} 5 x^{4}}{\left(\left(x^{5}\right)^{2}\right)^{2}}
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[\frac{x^{3}}{x^{5}}\right] = \frac{3 x^{2} x^{5} - x^{3} 5 x^{4}}{\left(x^{5}\right)^{2}} \]
\[ f(x) = \frac{x^{3}}{x^{5}} \]
\[ u = x^{3},\quad v = x^{5} \]
\[ u' = 3 x^{2},\quad v' = 5 x^{4} \]
\[ f'(x) = \frac{\left(3 x^{2}\right)\left(x^{5}\right) - \left(x^{3}\right)\left(5 x^{4}\right)}{\left(x^{5}\right)^{2}} \]
\[ f'(x) = \frac{3 x^{2} x^{5} - x^{3} 5 x^{4}}{\left(x^{5}\right)^{2}} \]
\[ f''(x) = \frac{\left(6 x x^{5} + 3 x^{2} 5 x^{4} - \left(3 x^{2} 5 x^{4} + x^{3} 20 x^{3}\right)\right) \left(x^{5}\right)^{2} - \left(3 x^{2} x^{5} - x^{3} 5 x^{4}\right) 2 x^{5} 5 x^{4}}{\left(\left(x^{5}\right)^{2}\right)^{2}} \]

Values of f and f' for x3x^{3} / x5x^{5}

xf(x)f'(x)
-20.250.25
-112
0.54-16
11-2
20.25-0.25
30.11111111-0.074074074

Questions

What is the derivative of x3x^{3} / x5x^{5}?

The derivative of x3x5\frac{x^{3}}{x^{5}} is 3x2x5−x35x4(x5)2\frac{3 x^{2} x^{5} - x^{3} 5 x^{4}}{\left(x^{5}\right)^{2}}.

What is the second derivative of x3x^{3} / x5x^{5}?

((6x * x5x^{5} + 3 * x2x^{2} * 5 * x4x^{4} - (3 * x2x^{2} * 5 * x4x^{4} + x3x^{3} * 20 * x3x^{3})) * (x5x^{5})^2 - (3 * x2x^{2} * x5x^{5} - x3x^{3} * 5 * x4x^{4}) * 2 * x5x^{5} * 5 * x4x^{4}) / ((x5x^{5})^2)^2.

Which rule do you use for x3x^{3} / x5x^{5}?

The quotient rule.

What is the slope of x3x^{3} / x5x^{5} at x = 1?

-2.

Related derivatives

    Derivative of x^3 / x^5: (3 * x^2 * x^5 - x^3 * 5 * x^4) / (x^5)^2 (with steps) | WordGPT