Derivative of
The derivative of is .
f(x) =
Type any function of x; the derivative is computed symbolically in your browser.
How to work it out
- 1
We differentiate with respect to x. The rule that applies is the quotient rule.
- 2
Quotient rule: . Let and .
- 3
Differentiate each piece:
- 4
Put them in the rule:
- 5
Simplify:
- 6
Differentiating once more gives the second derivative, which tells you about curvature:
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[\frac{\sin\left(x\right)}{x^{4}}\right] = \frac{\cos\left(x\right) x^{4} - \sin\left(x\right) 4 x^{3}}{\left(x^{4}\right)^{2}} \]
\[ f(x) = \frac{\sin\left(x\right)}{x^{4}} \]
\[ u = \sin\left(x\right),\quad v = x^{4} \]
\[ u' = \cos\left(x\right),\quad v' = 4 x^{3} \]
\[ f'(x) = \frac{\left(\cos\left(x\right)\right)\left(x^{4}\right) - \left(\sin\left(x\right)\right)\left(4 x^{3}\right)}{\left(x^{4}\right)^{2}} \]
\[ f'(x) = \frac{\cos\left(x\right) x^{4} - \sin\left(x\right) 4 x^{3}}{\left(x^{4}\right)^{2}} \]
\[ f''(x) = \frac{\left(-\left(\sin\left(x\right) x^{4}\right) + \cos\left(x\right) 4 x^{3} - \left(\cos\left(x\right) 4 x^{3} + \sin\left(x\right) 12 x^{2}\right)\right) \left(x^{4}\right)^{2} - \left(\cos\left(x\right) x^{4} - \sin\left(x\right) 4 x^{3}\right) 2 x^{4} 4 x^{3}}{\left(\left(x^{4}\right)^{2}\right)^{2}} \]Values of f and f' for sin(x) /
| x | f(x) | f'(x) |
|---|---|---|
| -2 | -0.056831089 | -0.13967136 |
| -1 | -0.84147098 | -2.8255816 |
| 0.5 | 7.6708086 | -47.325148 |
| 1 | 0.84147098 | -2.8255816 |
| 2 | 0.056831089 | -0.13967136 |
| 3 | 0.0017422223 | -0.014545093 |
Questions
What is the derivative of sin(x) / ?
The derivative of is .
What is the second derivative of sin(x) / ?
((-(sin(x) * ) + cos(x) * 4 * - (cos(x) * 4 * + sin(x) * 12 * )) * ()^2 - (cos(x) * - sin(x) * 4 * ) * 2 * * 4 * ) / (()^2)^2.
Which rule do you use for sin(x) / ?
The quotient rule.
What is the slope of sin(x) / at x = 1?
-2.8255816.