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Derivative of sin⁡(x2+1)\sin\left(x^{2} + 1\right)

The derivative of sin⁡(x2+1)\sin\left(x^{2} + 1\right) is cos⁡(x2+1)2x\cos\left(x^{2} + 1\right) 2 x.

f(x) =
ddx[sin⁡(x2+1)]=cos⁡(x2+1)2x\frac{d}{dx}\left[\sin\left(x^{2} + 1\right)\right] = \cos\left(x^{2} + 1\right) 2 x

Type any function of x; the derivative is computed symbolically in your browser.

Graph of f(x) = sin(x^2 + 1) and its derivative-3-2-1123-4-224slope -0.8323f(x)f'(x)tangent at x = 1
Graph of f(x) = sin(x^2 + 1) and its derivative. The dashed line is the tangent at x = 1; its slope is f'(1) = -0.83229.

How to work it out

  1. 1

    We differentiate f(x)=sin⁡(x2+1)f(x) = \sin\left(x^{2} + 1\right) with respect to x. The rule that applies is the chain rule.

    f(x)=sin⁡(x2+1)f(x) = \sin\left(x^{2} + 1\right)
  2. 2

    Chain rule: differentiate the outer function, keep the inside, then multiply by the derivative of the inside. The inside is g(x)=x2+1g(x) = x^{2} + 1.

    g(x)=x2+1,g′(x)=2xg(x) = x^{2} + 1,\quad g'(x) = 2 x
  3. 3

    The outer function is sin(u); its derivative evaluated at g(x), times g'(x):

    f′(x)=[cos⁡(u)]u=g(x)⋅g′(x)f'(x) = \left[\cos\left(u\right)\right]_{u=g(x)} \cdot g'(x)
  4. 4

    Simplify:

    f′(x)=cos⁡(x2+1)2xf'(x) = \cos\left(x^{2} + 1\right) 2 x
  5. 5

    Differentiating once more gives the second derivative, which tells you about curvature:

    f′′(x)=−(sin⁡(x2+1)2x2x)+2cos⁡(x2+1)f''(x) = -\left(\sin\left(x^{2} + 1\right) 2 x 2 x\right) + 2 \cos\left(x^{2} + 1\right)
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[\sin\left(x^{2} + 1\right)\right] = \cos\left(x^{2} + 1\right) 2 x \]
\[ f(x) = \sin\left(x^{2} + 1\right) \]
\[ g(x) = x^{2} + 1,\quad g'(x) = 2 x \]
\[ f'(x) = \left[\cos\left(u\right)\right]_{u=g(x)} \cdot g'(x) \]
\[ f'(x) = \cos\left(x^{2} + 1\right) 2 x \]
\[ f''(x) = -\left(\sin\left(x^{2} + 1\right) 2 x 2 x\right) + 2 \cos\left(x^{2} + 1\right) \]

Values of f and f' for sin(x2x^{2} + 1)

xf(x)f'(x)
-2-0.95892427-1.1346487
-10.909297430.83229367
0.50.948984620.31532236
10.90929743-0.83229367
2-0.958924271.1346487
3-0.54402111-5.0344292

Questions

What is the derivative of sin(x2x^{2} + 1)?

The derivative of sin⁡(x2+1)\sin\left(x^{2} + 1\right) is cos⁡(x2+1)2x\cos\left(x^{2} + 1\right) 2 x.

What is the second derivative of sin(x2x^{2} + 1)?

-(sin(x2x^{2} + 1) * 2x * 2x) + 2cos(x2x^{2} + 1).

Which rule do you use for sin(x2x^{2} + 1)?

The chain rule.

What is the slope of sin(x2x^{2} + 1) at x = 1?

-0.83229367.

Related derivatives

    Derivative of sin(x^2 + 1): cos(x^2 + 1) * 2x (with steps) | WordGPT