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Derivative of exsin⁡(x)\frac{e^{x}}{\sin\left(x\right)}

The derivative of exsin⁡(x)\frac{e^{x}}{\sin\left(x\right)} is exsin⁡(x)−excos⁡(x)sin⁡(x)2\frac{e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)}{\sin\left(x\right)^{2}}.

f(x) =
ddx[exsin⁡(x)]=exsin⁡(x)−excos⁡(x)sin⁡(x)2\frac{d}{dx}\left[\frac{e^{x}}{\sin\left(x\right)}\right] = \frac{e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)}{\sin\left(x\right)^{2}}

Type any function of x; the derivative is computed symbolically in your browser.

Graph of f(x) = exp(x) / sin(x) and its derivative-3-2-1123-2020406080slope 1.156f(x)f'(x)tangent at x = 1
Graph of f(x) = exp(x) / sin(x) and its derivative. The dashed line is the tangent at x = 1; its slope is f'(1) = 1.1562.

How to work it out

  1. 1

    We differentiate f(x)=exsin⁡(x)f(x) = \frac{e^{x}}{\sin\left(x\right)} with respect to x. The rule that applies is the quotient rule.

    f(x)=exsin⁡(x)f(x) = \frac{e^{x}}{\sin\left(x\right)}
  2. 2

    Quotient rule: (uv)′=u′v−uv′v2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^{2}}. Let u=exu = e^{x} and v=sin⁡(x)v = \sin\left(x\right).

    u=ex,v=sin⁡(x)u = e^{x},\quad v = \sin\left(x\right)
  3. 3

    Differentiate each piece:

    u′=ex,v′=cos⁡(x)u' = e^{x},\quad v' = \cos\left(x\right)
  4. 4

    Put them in the rule:

    f′(x)=(ex)(sin⁡(x))−(ex)(cos⁡(x))(sin⁡(x))2f'(x) = \frac{\left(e^{x}\right)\left(\sin\left(x\right)\right) - \left(e^{x}\right)\left(\cos\left(x\right)\right)}{\left(\sin\left(x\right)\right)^{2}}
  5. 5

    Simplify:

    f′(x)=exsin⁡(x)−excos⁡(x)sin⁡(x)2f'(x) = \frac{e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)}{\sin\left(x\right)^{2}}
  6. 6

    Differentiating once more gives the second derivative, which tells you about curvature:

    f′′(x)=(exsin⁡(x)+excos⁡(x)−(excos⁡(x)+ex−sin⁡(x)))sin⁡(x)2−(exsin⁡(x)−excos⁡(x))2sin⁡(x)cos⁡(x)(sin⁡(x)2)2f''(x) = \frac{\left(e^{x} \sin\left(x\right) + e^{x} \cos\left(x\right) - \left(e^{x} \cos\left(x\right) + e^{x} -\sin\left(x\right)\right)\right) \sin\left(x\right)^{2} - \left(e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)\right) 2 \sin\left(x\right) \cos\left(x\right)}{\left(\sin\left(x\right)^{2}\right)^{2}}
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[\frac{e^{x}}{\sin\left(x\right)}\right] = \frac{e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)}{\sin\left(x\right)^{2}} \]
\[ f(x) = \frac{e^{x}}{\sin\left(x\right)} \]
\[ u = e^{x},\quad v = \sin\left(x\right) \]
\[ u' = e^{x},\quad v' = \cos\left(x\right) \]
\[ f'(x) = \frac{\left(e^{x}\right)\left(\sin\left(x\right)\right) - \left(e^{x}\right)\left(\cos\left(x\right)\right)}{\left(\sin\left(x\right)\right)^{2}} \]
\[ f'(x) = \frac{e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)}{\sin\left(x\right)^{2}} \]
\[ f''(x) = \frac{\left(e^{x} \sin\left(x\right) + e^{x} \cos\left(x\right) - \left(e^{x} \cos\left(x\right) + e^{x} -\sin\left(x\right)\right)\right) \sin\left(x\right)^{2} - \left(e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)\right) 2 \sin\left(x\right) \cos\left(x\right)}{\left(\sin\left(x\right)^{2}\right)^{2}} \]

Values of f and f' for exp(x) / sin(x)

xf(x)f'(x)
-2-0.148835-0.080719538
-1-0.43718613-0.71790011
0.53.4389517-2.8560072
13.23039281.1561814
28.126115711.845094
3142.329481140.8067

Questions

What is the derivative of exp(x) / sin(x)?

The derivative of exsin⁡(x)\frac{e^{x}}{\sin\left(x\right)} is exsin⁡(x)−excos⁡(x)sin⁡(x)2\frac{e^{x} \sin\left(x\right) - e^{x} \cos\left(x\right)}{\sin\left(x\right)^{2}}.

What is the second derivative of exp(x) / sin(x)?

((exp(x) * sin(x) + exp(x) * cos(x) - (exp(x) * cos(x) + exp(x) * -sin(x))) * sin(x)^2 - (exp(x) * sin(x) - exp(x) * cos(x)) * 2sin(x) * cos(x)) / (sin(x)^2)^2.

Which rule do you use for exp(x) / sin(x)?

The quotient rule.

What is the slope of exp(x) / sin(x) at x = 1?

1.1561814.

Related derivatives

    Derivative of exp(x) / sin(x): (exp(x) * sin(x) - exp(x) * cos(x)) / sin(x)^2 (with steps) | WordGPT