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Derivative of e5xe^{5 x}

The derivative of e5xe^{5 x} is 5e5x5 e^{5 x}.

f(x) =
ddx[e5x]=5e5x\frac{d}{dx}\left[e^{5 x}\right] = 5 e^{5 x}

Type any function of x; the derivative is computed symbolically in your browser.

Graph of f(x) = exp(5x) and its derivative-3-2-11235e+51e+62e+62e+6slope 742.1f(x)f'(x)tangent at x = 1
Graph of f(x) = exp(5x) and its derivative. The dashed line is the tangent at x = 1; its slope is f'(1) = 742.07.

How to work it out

  1. 1

    We differentiate f(x)=e5xf(x) = e^{5 x} with respect to x. The rule that applies is the chain rule.

    f(x)=e5xf(x) = e^{5 x}
  2. 2

    Chain rule: differentiate the outer function, keep the inside, then multiply by the derivative of the inside. The inside is g(x)=5xg(x) = 5 x.

    g(x)=5x,g′(x)=5g(x) = 5 x,\quad g'(x) = 5
  3. 3

    The outer function is eue^{u}; its derivative evaluated at g(x), times g'(x):

    f′(x)=[eu]u=g(x)⋅g′(x)f'(x) = \left[e^{u}\right]_{u=g(x)} \cdot g'(x)
  4. 4

    Simplify:

    f′(x)=5e5xf'(x) = 5 e^{5 x}
  5. 5

    Differentiating once more gives the second derivative, which tells you about curvature:

    f′′(x)=25e5xf''(x) = 25 e^{5 x}
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[e^{5 x}\right] = 5 e^{5 x} \]
\[ f(x) = e^{5 x} \]
\[ g(x) = 5 x,\quad g'(x) = 5 \]
\[ f'(x) = \left[e^{u}\right]_{u=g(x)} \cdot g'(x) \]
\[ f'(x) = 5 e^{5 x} \]
\[ f''(x) = 25 e^{5 x} \]

Values of f and f' for exp(5x)

xf(x)f'(x)
-20.000045399930.00022699965
-10.0067379470.033689735
0.512.18249460.91247
1148.41316742.0658
222026.466110132.33
33269017.416345087

Questions

What is the derivative of exp(5x)?

The derivative of e5xe^{5 x} is 5e5x5 e^{5 x}.

What is the second derivative of exp(5x)?

25exp(5x).

Which rule do you use for exp(5x)?

The chain rule.

What is the slope of exp(5x) at x = 1?

742.0658.

Related derivatives

    Derivative of exp(5x): 5exp(5x) (with steps) | WordGPT