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Derivative of cos⁡(x2+1)\cos\left(x^{2} + 1\right)

The derivative of cos⁡(x2+1)\cos\left(x^{2} + 1\right) is −(sin⁡(x2+1)2x)-\left(\sin\left(x^{2} + 1\right) 2 x\right).

f(x) =
ddx[cos⁡(x2+1)]=−(sin⁡(x2+1)2x)\frac{d}{dx}\left[\cos\left(x^{2} + 1\right)\right] = -\left(\sin\left(x^{2} + 1\right) 2 x\right)

Type any function of x; the derivative is computed symbolically in your browser.

Graph of f(x) = cos(x^2 + 1) and its derivative-3-2-1123-4-2246slope -1.819f(x)f'(x)tangent at x = 1
Graph of f(x) = cos(x^2 + 1) and its derivative. The dashed line is the tangent at x = 1; its slope is f'(1) = -1.8186.

How to work it out

  1. 1

    We differentiate f(x)=cos⁡(x2+1)f(x) = \cos\left(x^{2} + 1\right) with respect to x. The rule that applies is the chain rule.

    f(x)=cos⁡(x2+1)f(x) = \cos\left(x^{2} + 1\right)
  2. 2

    Chain rule: differentiate the outer function, keep the inside, then multiply by the derivative of the inside. The inside is g(x)=x2+1g(x) = x^{2} + 1.

    g(x)=x2+1,g′(x)=2xg(x) = x^{2} + 1,\quad g'(x) = 2 x
  3. 3

    The outer function is cos(u); its derivative evaluated at g(x), times g'(x):

    f′(x)=[−sin⁡(u)]u=g(x)⋅g′(x)f'(x) = \left[-\sin\left(u\right)\right]_{u=g(x)} \cdot g'(x)
  4. 4

    Simplify:

    f′(x)=−(sin⁡(x2+1)2x)f'(x) = -\left(\sin\left(x^{2} + 1\right) 2 x\right)
  5. 5

    Differentiating once more gives the second derivative, which tells you about curvature:

    f′′(x)=−(cos⁡(x2+1)2x2x+2sin⁡(x2+1))f''(x) = -\left(\cos\left(x^{2} + 1\right) 2 x 2 x + 2 \sin\left(x^{2} + 1\right)\right)
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[\cos\left(x^{2} + 1\right)\right] = -\left(\sin\left(x^{2} + 1\right) 2 x\right) \]
\[ f(x) = \cos\left(x^{2} + 1\right) \]
\[ g(x) = x^{2} + 1,\quad g'(x) = 2 x \]
\[ f'(x) = \left[-\sin\left(u\right)\right]_{u=g(x)} \cdot g'(x) \]
\[ f'(x) = -\left(\sin\left(x^{2} + 1\right) 2 x\right) \]
\[ f''(x) = -\left(\cos\left(x^{2} + 1\right) 2 x 2 x + 2 \sin\left(x^{2} + 1\right)\right) \]

Values of f and f' for cos(x2x^{2} + 1)

xf(x)f'(x)
-20.28366219-3.8356971
-1-0.416146841.8185949
0.50.31532236-0.94898462
1-0.41614684-1.8185949
20.283662193.8356971
3-0.839071533.2641267

Questions

What is the derivative of cos(x2x^{2} + 1)?

The derivative of cos⁡(x2+1)\cos\left(x^{2} + 1\right) is −(sin⁡(x2+1)2x)-\left(\sin\left(x^{2} + 1\right) 2 x\right).

What is the second derivative of cos(x2x^{2} + 1)?

-(cos(x2x^{2} + 1) * 2x * 2x + 2sin(x2x^{2} + 1)).

Which rule do you use for cos(x2x^{2} + 1)?

The chain rule.

What is the slope of cos(x2x^{2} + 1) at x = 1?

-1.8185949.

Related derivatives

    Derivative of cos(x^2 + 1): -(sin(x^2 + 1) * 2x) (with steps) | WordGPT