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Derivative of arctan⁡(x)\arctan\left(x\right)

The derivative of arctan⁡(x)\arctan\left(x\right) is 11+x2\frac{1}{1 + x^{2}}.

f(x) =
ddx[arctan⁡(x)]=11+x2\frac{d}{dx}\left[\arctan\left(x\right)\right] = \frac{1}{1 + x^{2}}

Type any function of x; the derivative is computed symbolically in your browser.

Graph of f(x) = atan(x) and its derivative-3-2-1123-1.5-1-0.50.511.5slope 0.5f(x)f'(x)tangent at x = 1
Graph of f(x) = atan(x) and its derivative. The dashed line is the tangent at x = 1; its slope is f'(1) = 0.5.

How to work it out

  1. 1

    We differentiate f(x)=arctan⁡(x)f(x) = \arctan\left(x\right) with respect to x. The rule that applies is the standard derivative.

    f(x)=arctan⁡(x)f(x) = \arctan\left(x\right)
  2. 2

    This is a standard derivative from the table.

  3. 3

    Simplify:

    f′(x)=11+x2f'(x) = \frac{1}{1 + x^{2}}
  4. 4

    Differentiating once more gives the second derivative, which tells you about curvature:

    f′′(x)=−(2x)(1+x2)2f''(x) = \frac{-\left(2 x\right)}{\left(1 + x^{2}\right)^{2}}
LaTeX source of the formulas on this page
\[ \frac{d}{dx}\left[\arctan\left(x\right)\right] = \frac{1}{1 + x^{2}} \]
\[ f(x) = \arctan\left(x\right) \]
\[ f'(x) = \frac{1}{1 + x^{2}} \]
\[ f''(x) = \frac{-\left(2 x\right)}{\left(1 + x^{2}\right)^{2}} \]

Values of f and f' for atan(x)

xf(x)f'(x)
-2-1.10714870.2
-1-0.785398160.5
0.50.463647610.8
10.785398160.5
21.10714870.2
31.24904580.1

Questions

What is the derivative of atan(x)?

The derivative of arctan⁡(x)\arctan\left(x\right) is 11+x2\frac{1}{1 + x^{2}}.

What is the second derivative of atan(x)?

-(2x) / (1 + x2x^{2})^2.

Which rule do you use for atan(x)?

The standard derivative.

What is the slope of atan(x) at x = 1?

0.5.

Related derivatives

    Derivative of atan(x): 1 / (1 + x^2) (with steps) | WordGPT