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Which is bigger, 5195^{19} or 19519^{5}?

5195^{19} is bigger: 5195^{19} = 1.90734 × 101310^{13} and 19519^{5} = 2476099.

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The curve ln x / x, which decides every comparison of a^b with b^a246810121416182022-0.10.10.20.30.4x = 5x = 19peak at eln x / x
The curve ln x / x, which decides every comparison of a^b with b^a. 5^19 against 19^5 is the same question as which of the two marked points is higher; the curve peaks at x = e.

How to work it out

  1. 1

    Compute both exactly: 5195^{19} = 19073486328125 and 19519^{5} = 2476099.

  2. 2

    So 5195^{19} is bigger.

  3. 3

    The reason: taking logs, aba^{b} against bab^{a} is the same as ln⁡aa\frac{\ln a}{a} against ln⁡bb\frac{\ln b}{b}. The function ln⁡xx\frac{\ln x}{x} rises until x=e≈2.718x = e \approx 2.718 and falls afterwards. Both 5 and 19 are past e, where the function is decreasing, so the larger exponent loses and 5195^{19} > 19519^{5}.

    ln⁡55 > ln⁡1919\frac{\ln 5}{5}\ >\ \frac{\ln 19}{19}
LaTeX source of the formulas on this page
\[ 5^{19} = 19073486328125\ >\ 19^{5} = 2476099 \]
\[ \frac{\ln 5}{5}\ >\ \frac{\ln 19}{19} \]

Questions

Which is bigger, 5195^{19} or 19519^{5}?

5195^{19} is bigger: 5195^{19} = 1.90734 × 101310^{13} and 19519^{5} = 2476099.

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