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Which is bigger, 2112^{11} or 11211^{2}?

2112^{11} is bigger: 2112^{11} = 2048 and 11211^{2} = 121.

The curve ln x / x, which decides every comparison of a^b with b^a2468101214-0.4-0.20.20.4x = 2x = 11peak at eln x / x
The curve ln x / x, which decides every comparison of a^b with b^a. 2^11 against 11^2 is the same question as which of the two marked points is higher; the curve peaks at x = e.

How to work it out

  1. 1

    Compute both exactly: 2112^{11} = 2048 and 11211^{2} = 121.

  2. 2

    So 2112^{11} is bigger.

  3. 3

    The reason: taking logs, aba^{b} against bab^{a} is the same as ln⁡aa\frac{\ln a}{a} against ln⁡bb\frac{\ln b}{b}. The function ln⁡xx\frac{\ln x}{x} rises until x=e≈2.718x = e \approx 2.718 and falls afterwards. For 2 and 11 it depends: 242^{4} = 424^{2} are equal, 232^{3} < 323^{2}, and 2b2^{b} > b2b^{2} for every b ≥ 5.

    ln⁡22 > ln⁡1111\frac{\ln 2}{2}\ >\ \frac{\ln 11}{11}
LaTeX source of the formulas on this page
\[ 2^{11} = 2048\ >\ 11^{2} = 121 \]
\[ \frac{\ln 2}{2}\ >\ \frac{\ln 11}{11} \]

Questions

Which is bigger, 2112^{11} or 11211^{2}?

2112^{11} is bigger: 2112^{11} = 2048 and 11211^{2} = 121.

Similar comparisons

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