Square root of 9508

The square root of 9508 is 97.508974 (rounded to 6 decimal places). In simplest radical form it is 2√2377.

Square root of 9508

Pick any whole number from 1 to 10,000.

\sqrt{9508} = 2\sqrt{2377} \approx 97.508974

How to work it out

1
The square root of 9508 is the number that multiplied by itself gives 9508.
2
9508 is between the perfect squares 97² = 9409 and 98² = 9604, so its square root is between 97 and 98.
3
Pull out the biggest square factor: 9508 = 4 × 2377, so
$\sqrt{9508} = \sqrt{4 \times 2377} = 2\sqrt{2377}$
4
A calculator, or long division of digits, gives
$\sqrt{9508} \approx 97.508974$

LaTeX source of the formulas on this page

\[ \sqrt{9508} = 2\sqrt{2377} \approx 97.508974 \]
\[ \sqrt{9508} = \sqrt{4 \times 2377} = 2\sqrt{2377} \]
\[ \sqrt{9508} \approx 97.508974 \]

What is the square root of 9508?

The square root of 9508 is 97.508974 (rounded to 6 decimal places). In simplest radical form it is 2√2377.

Is 9508 a perfect square?

No. It lies between 97² = 9409 and 98² = 9604.

What is 9508 squared?

9508 × 9508 = 90402064.

What is the square root of 9508 rounded to 2 decimals?

97.51.