Square root of 9380

The square root of 9380 is 96.8504 (rounded to 6 decimal places). In simplest radical form it is 2√2345.

Square root of 9380

Pick any whole number from 1 to 10,000.

\sqrt{9380} = 2\sqrt{2345} \approx 96.8504

How to work it out

1
The square root of 9380 is the number that multiplied by itself gives 9380.
2
9380 is between the perfect squares 96² = 9216 and 97² = 9409, so its square root is between 96 and 97.
3
Pull out the biggest square factor: 9380 = 4 × 2345, so
$\sqrt{9380} = \sqrt{4 \times 2345} = 2\sqrt{2345}$
4
A calculator, or long division of digits, gives
$\sqrt{9380} \approx 96.8504$

LaTeX source of the formulas on this page

\[ \sqrt{9380} = 2\sqrt{2345} \approx 96.8504 \]
\[ \sqrt{9380} = \sqrt{4 \times 2345} = 2\sqrt{2345} \]
\[ \sqrt{9380} \approx 96.8504 \]

What is the square root of 9380?

The square root of 9380 is 96.8504 (rounded to 6 decimal places). In simplest radical form it is 2√2345.

Is 9380 a perfect square?

No. It lies between 96² = 9216 and 97² = 9409.

What is 9380 squared?

9380 × 9380 = 87984400.

What is the square root of 9380 rounded to 2 decimals?

96.85.