Square root of 7480

The square root of 7480 is 86.486993 (rounded to 6 decimal places). In simplest radical form it is 2√1870.

Square root of 7480

Pick any whole number from 1 to 10,000.

\sqrt{7480} = 2\sqrt{1870} \approx 86.486993

How to work it out

1
The square root of 7480 is the number that multiplied by itself gives 7480.
2
7480 is between the perfect squares 86² = 7396 and 87² = 7569, so its square root is between 86 and 87.
3
Pull out the biggest square factor: 7480 = 4 × 1870, so
$\sqrt{7480} = \sqrt{4 \times 1870} = 2\sqrt{1870}$
4
A calculator, or long division of digits, gives
$\sqrt{7480} \approx 86.486993$

LaTeX source of the formulas on this page

\[ \sqrt{7480} = 2\sqrt{1870} \approx 86.486993 \]
\[ \sqrt{7480} = \sqrt{4 \times 1870} = 2\sqrt{1870} \]
\[ \sqrt{7480} \approx 86.486993 \]

What is the square root of 7480?

The square root of 7480 is 86.486993 (rounded to 6 decimal places). In simplest radical form it is 2√1870.

Is 7480 a perfect square?

No. It lies between 86² = 7396 and 87² = 7569.

What is 7480 squared?

7480 × 7480 = 55950400.

What is the square root of 7480 rounded to 2 decimals?

86.49.