Square root of 7352

The square root of 7352 is 85.743804 (rounded to 6 decimal places). In simplest radical form it is 2√1838.

Square root of 7352

Pick any whole number from 1 to 10,000.

\sqrt{7352} = 2\sqrt{1838} \approx 85.743804

How to work it out

1
The square root of 7352 is the number that multiplied by itself gives 7352.
2
7352 is between the perfect squares 85² = 7225 and 86² = 7396, so its square root is between 85 and 86.
3
Pull out the biggest square factor: 7352 = 4 × 1838, so
$\sqrt{7352} = \sqrt{4 \times 1838} = 2\sqrt{1838}$
4
A calculator, or long division of digits, gives
$\sqrt{7352} \approx 85.743804$

LaTeX source of the formulas on this page

\[ \sqrt{7352} = 2\sqrt{1838} \approx 85.743804 \]
\[ \sqrt{7352} = \sqrt{4 \times 1838} = 2\sqrt{1838} \]
\[ \sqrt{7352} \approx 85.743804 \]

What is the square root of 7352?

The square root of 7352 is 85.743804 (rounded to 6 decimal places). In simplest radical form it is 2√1838.

Is 7352 a perfect square?

No. It lies between 85² = 7225 and 86² = 7396.

What is 7352 squared?

7352 × 7352 = 54051904.

What is the square root of 7352 rounded to 2 decimals?

85.74.