Square root of 6940

The square root of 6940 is 83.306662 (rounded to 6 decimal places). In simplest radical form it is 2√1735.

Square root of 6940

Pick any whole number from 1 to 10,000.

\sqrt{6940} = 2\sqrt{1735} \approx 83.306662

How to work it out

1
The square root of 6940 is the number that multiplied by itself gives 6940.
2
6940 is between the perfect squares 83² = 6889 and 84² = 7056, so its square root is between 83 and 84.
3
Pull out the biggest square factor: 6940 = 4 × 1735, so
$\sqrt{6940} = \sqrt{4 \times 1735} = 2\sqrt{1735}$
4
A calculator, or long division of digits, gives
$\sqrt{6940} \approx 83.306662$

LaTeX source of the formulas on this page

\[ \sqrt{6940} = 2\sqrt{1735} \approx 83.306662 \]
\[ \sqrt{6940} = \sqrt{4 \times 1735} = 2\sqrt{1735} \]
\[ \sqrt{6940} \approx 83.306662 \]

What is the square root of 6940?

The square root of 6940 is 83.306662 (rounded to 6 decimal places). In simplest radical form it is 2√1735.

Is 6940 a perfect square?

No. It lies between 83² = 6889 and 84² = 7056.

What is 6940 squared?

6940 × 6940 = 48163600.

What is the square root of 6940 rounded to 2 decimals?

83.31.