Square root of 6828

The square root of 6828 is 82.631713 (rounded to 6 decimal places). In simplest radical form it is 2√1707.

Square root of 6828

Pick any whole number from 1 to 10,000.

\sqrt{6828} = 2\sqrt{1707} \approx 82.631713

How to work it out

1
The square root of 6828 is the number that multiplied by itself gives 6828.
2
6828 is between the perfect squares 82² = 6724 and 83² = 6889, so its square root is between 82 and 83.
3
Pull out the biggest square factor: 6828 = 4 × 1707, so
$\sqrt{6828} = \sqrt{4 \times 1707} = 2\sqrt{1707}$
4
A calculator, or long division of digits, gives
$\sqrt{6828} \approx 82.631713$

LaTeX source of the formulas on this page

\[ \sqrt{6828} = 2\sqrt{1707} \approx 82.631713 \]
\[ \sqrt{6828} = \sqrt{4 \times 1707} = 2\sqrt{1707} \]
\[ \sqrt{6828} \approx 82.631713 \]

What is the square root of 6828?

The square root of 6828 is 82.631713 (rounded to 6 decimal places). In simplest radical form it is 2√1707.

Is 6828 a perfect square?

No. It lies between 82² = 6724 and 83² = 6889.

What is 6828 squared?

6828 × 6828 = 46621584.

What is the square root of 6828 rounded to 2 decimals?

82.63.