Square root of 6492

The square root of 6492 is 80.572948 (rounded to 6 decimal places). In simplest radical form it is 2√1623.

Square root of 6492

Pick any whole number from 1 to 10,000.

\sqrt{6492} = 2\sqrt{1623} \approx 80.572948

How to work it out

1
The square root of 6492 is the number that multiplied by itself gives 6492.
2
6492 is between the perfect squares 80² = 6400 and 81² = 6561, so its square root is between 80 and 81.
3
Pull out the biggest square factor: 6492 = 4 × 1623, so
$\sqrt{6492} = \sqrt{4 \times 1623} = 2\sqrt{1623}$
4
A calculator, or long division of digits, gives
$\sqrt{6492} \approx 80.572948$

LaTeX source of the formulas on this page

\[ \sqrt{6492} = 2\sqrt{1623} \approx 80.572948 \]
\[ \sqrt{6492} = \sqrt{4 \times 1623} = 2\sqrt{1623} \]
\[ \sqrt{6492} \approx 80.572948 \]

What is the square root of 6492?

The square root of 6492 is 80.572948 (rounded to 6 decimal places). In simplest radical form it is 2√1623.

Is 6492 a perfect square?

No. It lies between 80² = 6400 and 81² = 6561.

What is 6492 squared?

6492 × 6492 = 42146064.

What is the square root of 6492 rounded to 2 decimals?

80.57.