Square root of 5238

The square root of 5238 is 72.374028 (rounded to 6 decimal places). In simplest radical form it is 3√582.

Square root of 5238

Pick any whole number from 1 to 10,000.

\sqrt{5238} = 3\sqrt{582} \approx 72.374028

How to work it out

1
The square root of 5238 is the number that multiplied by itself gives 5238.
2
5238 is between the perfect squares 72² = 5184 and 73² = 5329, so its square root is between 72 and 73.
3
Pull out the biggest square factor: 5238 = 9 × 582, so
$\sqrt{5238} = \sqrt{9 \times 582} = 3\sqrt{582}$
4
A calculator, or long division of digits, gives
$\sqrt{5238} \approx 72.374028$

LaTeX source of the formulas on this page

\[ \sqrt{5238} = 3\sqrt{582} \approx 72.374028 \]
\[ \sqrt{5238} = \sqrt{9 \times 582} = 3\sqrt{582} \]
\[ \sqrt{5238} \approx 72.374028 \]

What is the square root of 5238?

The square root of 5238 is 72.374028 (rounded to 6 decimal places). In simplest radical form it is 3√582.

Is 5238 a perfect square?

No. It lies between 72² = 5184 and 73² = 5329.

What is 5238 squared?

5238 × 5238 = 27436644.

What is the square root of 5238 rounded to 2 decimals?

72.37.