Square root of 4640

The square root of 4640 is 68.117545 (rounded to 6 decimal places). In simplest radical form it is 4√290.

Square root of 4640

Pick any whole number from 1 to 10,000.

\sqrt{4640} = 4\sqrt{290} \approx 68.117545

How to work it out

1
The square root of 4640 is the number that multiplied by itself gives 4640.
2
4640 is between the perfect squares 68² = 4624 and 69² = 4761, so its square root is between 68 and 69.
3
Pull out the biggest square factor: 4640 = 16 × 290, so
$\sqrt{4640} = \sqrt{16 \times 290} = 4\sqrt{290}$
4
A calculator, or long division of digits, gives
$\sqrt{4640} \approx 68.117545$

LaTeX source of the formulas on this page

\[ \sqrt{4640} = 4\sqrt{290} \approx 68.117545 \]
\[ \sqrt{4640} = \sqrt{16 \times 290} = 4\sqrt{290} \]
\[ \sqrt{4640} \approx 68.117545 \]

What is the square root of 4640?

The square root of 4640 is 68.117545 (rounded to 6 decimal places). In simplest radical form it is 4√290.

Is 4640 a perfect square?

No. It lies between 68² = 4624 and 69² = 4761.

What is 4640 squared?

4640 × 4640 = 21529600.

What is the square root of 4640 rounded to 2 decimals?

68.12.