Square root of 4080

The square root of 4080 is 63.874878 (rounded to 6 decimal places). In simplest radical form it is 4√255.

Square root of 4080

Pick any whole number from 1 to 10,000.

\sqrt{4080} = 4\sqrt{255} \approx 63.874878

How to work it out

1
The square root of 4080 is the number that multiplied by itself gives 4080.
2
4080 is between the perfect squares 63² = 3969 and 64² = 4096, so its square root is between 63 and 64.
3
Pull out the biggest square factor: 4080 = 16 × 255, so
$\sqrt{4080} = \sqrt{16 \times 255} = 4\sqrt{255}$
4
A calculator, or long division of digits, gives
$\sqrt{4080} \approx 63.874878$

LaTeX source of the formulas on this page

\[ \sqrt{4080} = 4\sqrt{255} \approx 63.874878 \]
\[ \sqrt{4080} = \sqrt{16 \times 255} = 4\sqrt{255} \]
\[ \sqrt{4080} \approx 63.874878 \]

What is the square root of 4080?

The square root of 4080 is 63.874878 (rounded to 6 decimal places). In simplest radical form it is 4√255.

Is 4080 a perfect square?

No. It lies between 63² = 3969 and 64² = 4096.

What is 4080 squared?

4080 × 4080 = 16646400.

What is the square root of 4080 rounded to 2 decimals?

63.87.