Square root of 2738

The square root of 2738 is 52.325902 (rounded to 6 decimal places). In simplest radical form it is 37√2.

Square root of 2738

Pick any whole number from 1 to 10,000.

\sqrt{2738} = 37\sqrt{2} \approx 52.325902

How to work it out

1
The square root of 2738 is the number that multiplied by itself gives 2738.
2
2738 is between the perfect squares 52² = 2704 and 53² = 2809, so its square root is between 52 and 53.
3
Pull out the biggest square factor: 2738 = 1369 × 2, so
$\sqrt{2738} = \sqrt{1369 \times 2} = 37\sqrt{2}$
4
A calculator, or long division of digits, gives
$\sqrt{2738} \approx 52.325902$

LaTeX source of the formulas on this page

\[ \sqrt{2738} = 37\sqrt{2} \approx 52.325902 \]
\[ \sqrt{2738} = \sqrt{1369 \times 2} = 37\sqrt{2} \]
\[ \sqrt{2738} \approx 52.325902 \]

What is the square root of 2738?

The square root of 2738 is 52.325902 (rounded to 6 decimal places). In simplest radical form it is 37√2.

Is 2738 a perfect square?

No. It lies between 52² = 2704 and 53² = 2809.

What is 2738 squared?

2738 × 2738 = 7496644.

What is the square root of 2738 rounded to 2 decimals?

52.33.