Square root of 2640

The square root of 2640 is 51.38093 (rounded to 6 decimal places). In simplest radical form it is 4√165.

Square root of 2640

Pick any whole number from 1 to 10,000.

\sqrt{2640} = 4\sqrt{165} \approx 51.38093

How to work it out

1
The square root of 2640 is the number that multiplied by itself gives 2640.
2
2640 is between the perfect squares 51² = 2601 and 52² = 2704, so its square root is between 51 and 52.
3
Pull out the biggest square factor: 2640 = 16 × 165, so
$\sqrt{2640} = \sqrt{16 \times 165} = 4\sqrt{165}$
4
A calculator, or long division of digits, gives
$\sqrt{2640} \approx 51.38093$

LaTeX source of the formulas on this page

\[ \sqrt{2640} = 4\sqrt{165} \approx 51.38093 \]
\[ \sqrt{2640} = \sqrt{16 \times 165} = 4\sqrt{165} \]
\[ \sqrt{2640} \approx 51.38093 \]

What is the square root of 2640?

The square root of 2640 is 51.38093 (rounded to 6 decimal places). In simplest radical form it is 4√165.

Is 2640 a perfect square?

No. It lies between 51² = 2601 and 52² = 2704.

What is 2640 squared?

2640 × 2640 = 6969600.

What is the square root of 2640 rounded to 2 decimals?

51.38.